LanguageFeatures/Extension-methods/generic_parameter_inference_A01_t06.dart

/*
 * Copyright (c) 2019, the Dart project authors.  Please see the AUTHORS file
 * for details. All rights reserved. Use of this source code is governed by a
 * BSD-style license that can be found in the LICENSE file.
 */
/**
 * @assertion If both the extension and the method is generic, then inference
 * must infer the extension type parameters first, to figure out whether the
 * extension applies, and only then start inferring method type parameters. As
 * mentioned above, the inference is similar to other cases of chained inference.
 * @description Check that if inference is performed in a single step then it
 * can yield SuperList<Object>(list).checkme<int>(42) without an error.
 * @author iarkh@unipro.ru
 */


import "../../Utils/expect.dart";

extension SuperList<T> on List<T> {
  void checkme<R extends T>(R i) {
    Expect.equals(42, i);
  }
}

main() {
  List<String> list = [];
  SuperList<Object>(list).checkme<int>(42);
}