| Problems reported: | |
| parser/patterns/declaredVariable_inPatternAssignment_usingFinal:2:13: Variable 'd' can't be declared in a pattern assignment. | |
| [a, final d] = y; | |
| ^ | |
| beginCompilationUnit(void) | |
| beginMetadataStar(void) | |
| endMetadataStar(0) | |
| beginTopLevelMember(void) | |
| beginTopLevelMethod(, null, null) | |
| handleVoidKeyword(void) | |
| handleIdentifier(f, topLevelFunctionDeclaration) | |
| handleNoTypeVariables(() | |
| beginFormalParameters((, MemberKind.TopLevelMethod) | |
| endFormalParameters(0, (, ), MemberKind.TopLevelMethod) | |
| handleAsyncModifier(null, null) | |
| beginBlockFunctionBody({) | |
| beginPattern({) | |
| handleNoTypeArguments([) | |
| beginPattern([) | |
| handleAssignedVariablePattern(a) | |
| endPattern(a) | |
| beginPattern(,) | |
| handleNoType(final) | |
| handleRecoverableError(Message[Template(PatternAssignmentDeclaresVariable), Variable 'd' can't be declared in a pattern assignment., Try using a preexisting variable or changing the assignment to a pattern variable declaration., {variableName: d}], d, d) | |
| handleDeclaredVariablePattern(final, d, true) | |
| endPattern(d) | |
| handleListPattern(2, [, ]) | |
| endPattern(]) | |
| handleIdentifier(y, expression) | |
| handleSendWithoutArguments(y, y, ;) | |
| handlePatternAssignment(=) | |
| handleExpressionStatement([, ;) | |
| endBlockFunctionBody(1, {, }) | |
| endTopLevelMethod(void, null, }) | |
| endTopLevelDeclaration(}) | |
| endCompilationUnit(1, ) |