| Problems reported: |
| |
| parser/patterns/declaredVariable_inPatternAssignment_usingVar:2:11: Variable 'd' can't be declared in a pattern assignment. |
| [a, var d] = y; |
| ^ |
| |
| beginCompilationUnit(void) |
| beginMetadataStar(void) |
| endMetadataStar(0) |
| beginTopLevelMember(void) |
| beginTopLevelMethod(, null, null) |
| handleVoidKeyword(void) |
| handleIdentifier(f, topLevelFunctionDeclaration) |
| handleNoTypeVariables(() |
| beginFormalParameters((, MemberKind.TopLevelMethod) |
| endFormalParameters(0, (, ), MemberKind.TopLevelMethod) |
| handleAsyncModifier(null, null) |
| beginBlockFunctionBody({) |
| beginPattern({) |
| handleNoTypeArguments([) |
| beginPattern([) |
| handleAssignedVariablePattern(a) |
| endPattern(a) |
| beginPattern(,) |
| handleNoType(var) |
| handleRecoverableError(Message[PatternAssignmentDeclaresVariable, Variable 'd' can't be declared in a pattern assignment., Try using a preexisting variable or changing the assignment to a pattern variable declaration., {name: d}], d, d) |
| handleDeclaredVariablePattern(var, d, true) |
| endPattern(d) |
| handleListPattern(2, [, ]) |
| endPattern(]) |
| handleIdentifier(y, expression) |
| handleNoTypeArguments(;) |
| handleNoArguments(;) |
| handleSend(y, ;) |
| handlePatternAssignment(=) |
| handleExpressionStatement(;) |
| endBlockFunctionBody(1, {, }) |
| endTopLevelMethod(void, null, }) |
| endTopLevelDeclaration() |
| endCompilationUnit(1, ) |
