| // Copyright (c) 2012, the Dart project authors. Please see the AUTHORS file |
| // for details. All rights reserved. Use of this source code is governed by a |
| // BSD-style license that can be found in the LICENSE file. |
| |
| library CountTest; |
| import '../../pkg/unittest/lib/unittest.dart'; |
| import 'dart:isolate'; |
| |
| void countMessages() { |
| int count = 0; |
| port.receive((int message, SendPort replyTo) { |
| if (message == -1) { |
| expect(count, 10); |
| replyTo.send(-1, null); |
| port.close(); |
| return; |
| } |
| expect(message, count); |
| count++; |
| replyTo.send(message * 2, null); |
| }); |
| } |
| |
| void main() { |
| test("count 10 consecutive messages", () { |
| int count = 0; |
| SendPort remote = spawnFunction(countMessages); |
| ReceivePort local = new ReceivePort(); |
| SendPort reply = local.toSendPort(); |
| |
| local.receive(expectAsync2((int message, SendPort replyTo) { |
| if (message == -1) { |
| // [count] is '11' because when we sent '9' to [remote], |
| // the other isolate will send another message '18', that this |
| // isolate will receive. Then this isolate will send '10' to |
| // [remote] and increment [count]. Note that this last '10' |
| // message will not be received by the other isolate, since it |
| // received '-1' before. |
| expect(count, 11); |
| local.close(); |
| return; |
| } |
| |
| expect(message, (count - 1) * 2); |
| remote.send(count++, reply); |
| if (count == 10) { |
| remote.send(-1, reply); |
| } |
| }, count: 11)); |
| remote.send(count++, reply); |
| }); |
| } |