| commit | 46ac1f653f12168991787a7605a3e4000aaa7324 | [log] [tgz] |
|---|---|---|
| author | Vyacheslav Egorov <vegorov@google.com> | Thu Aug 31 11:47:54 2023 +0000 |
| committer | Commit Queue <dart-scoped@luci-project-accounts.iam.gserviceaccount.com> | Thu Aug 31 11:47:54 2023 +0000 |
| tree | ff344f4af6b26f002e108a1e5f97c722fef4c824 | |
| parent | b25873f11c68772408f6a4aea5f5c961f31ac9f7 [diff] |
[vm] Treat Future.then(..., onError:...) as catch all handler
Commit a52f2b9 which reworked awaiter stack unwinding and its
integration with debugger introduced the following regression:
it stopped treating `Future` listeners which had both `onValue`
and `onError` callbacks as catch all exception handlers. Only
listners with `onError` callback (those created with
`Future.onError`) were treated as a catch all handler.
This meant that debugger started to treat exceptions in the
code below as uncaught:
```
Future<void> foo() {
await 0;
throw '';
}
await foo().then(..., onError: (e, st) {
});
```
This change fixes this regression by checking if
`FutureListener.state & stateCatchError != 0` instead of
more narrow `FutureListener.state == stateCatchError` which
only detects listeners which only catch errors but do not
handle values. The new predicate matches
`FutureListener.handlesError`.
This relands 38e0046cad6149c531c00cc4f479fb14ff026514
with a fix to ensure that we correctly detect `onError`
callbacks which simply forward to a suspended async
function. We do this by marking FutureListener's that originate
from `await` using a bit in the state.
Fixes https://github.com/dart-lang/sdk/issues/53334
TEST=service/pause_on_unhandled_async_exceptions{_zones,}_test
Fixed: 53334
CoreLibraryReviewExempt: No fundamental changes to _FutureListener implementation, just additional bit to detect that this listener originates from await
Change-Id: I90385fc619cbb52925e075dd5c7b171a31ca4cab
Reviewed-on: https://dart-review.googlesource.com/c/sdk/+/323481
Commit-Queue: Slava Egorov <vegorov@google.com>
Reviewed-by: Alexander Markov <alexmarkov@google.com>
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