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// Copyright (c) 2021, the Dart project authors. Please see the AUTHORS file
// for details. All rights reserved. Use of this source code is governed by a
// BSD-style license that can be found in the LICENSE file.
/// @assertion Allow generic function types as type arguments and bounds
/// The language disallows generic function types as type arguments and bounds.
/// late List<T Function<T>(T)> idFunctions; // INVALID.
/// var callback = [foo<T>(T value) => value]; // Inferred as above, then invalid.
/// late S Function<S extends T Function<T>(T)>(S) f; // INVALID.
/// We remove that restriction, so a type argument and a bound can be a generic
/// function type.
/// This requires no new syntax, and in some cases only the removal of a single
/// check. There might be some platforms where the implementation currently
/// assumes that generic function types cannot occur as the value of type
/// variables (an proof-of-concept attempt hit an assert in the VM). Such
/// assumptions will need to be flushed out with tests and fixed.
/// Because we already infer List<T Function<T>(T)> in the code above, this
/// change will not affect type inference, it will just make the inferred type
/// not be an error afterwards.
/// We do not expect the removal of this restriction to affect the feasibility of
/// type inference. After all, it's already possible to have a generic function
/// type occurring covariantly in a type argument, like List<T Function<T>(T)
/// Function()>.
/// @description Checks that generic function can be a function type alias
/// argument and bound.
/// @author
import "../../Utils/expect.dart";
typedef void TEST1<T extends void Function<TT>()>();
typedef void TEST2<T extends TT Function<TT>()>();
typedef void TEST3<T extends void Function<TT>(TT)>();
typedef void TEST4<T extends TT Function<TT>(TT)>();
typedef exp = void Function();
main() {
Expect.equals(exp, TEST1);
Expect.equals(exp, TEST2);
Expect.equals(exp, TEST3);
Expect.equals(exp, TEST4);