LanguageFeatures/Extension-methods/call_member_t06.dart

// Copyright (c) 2019, the Dart project authors.  Please see the AUTHORS file
// for details. All rights reserved. Use of this source code is governed by a
// BSD-style license that can be found in the LICENSE file.

/// @assertion Any expression of the form e1(args) or e1<types>(args) where e1
/// does not denote a method, and where the static type of e1 is not a function
/// type, an interface type declaring a call method, or dynamic, will currently
/// be a compile-time error. If the static type of e1 is an interface type
/// declaring a call getter, then this stays a compile-time error. Otherwise we
/// check for extensions applying to the static type of e1 and declaring a call
/// member. If one such most specific extension exists, and it declares a call
/// extension method, then the expression is equivalent to e1.call(args) or
/// e1.call<typeS>(args). Otherwise it is still a compile-time error.
///
/// @description Check that extension with the 'call' method is applicable, then
/// it is called. Test type arguments
/// @author sgrekhov@unipro.ru


import "../../Utils/expect.dart";

class C<T extends num> {
}

extension IntExtWithCall<T extends num> on C<T> {
  String call(int v, String m) => "Result: $m $v";
}

main() {
  C<int> c = new C<int>();
  Expect.equals("Result: XxX 42", c(42, "XxX"));
}